Seeing that two of the dogs I brought in for CERF
exams were black Labs, the vet's assistant started telling me about
her yellow Lab bitch.
She was planning to breed her bitch - had bred her before to a yellow
stud, and was planning this time to use a chocolate belonging to
the same owner.
We talked at length, and finally I asked her if she knew that the
breedings she planned (chocolate x yellow) would almost certainly
produce black puppies. "Why,
yes," she answered, I got six black and six yellow last time." In
this article, I shall try to explain the inheritance of the black,
yellow, and chocolate colors in Labradors. I will
show how to use information
from pedigrees and previous breedings to predict pup colors, and
make clear why a chocolate x yellow breeding is expected
to produce black pups, but
black from a yellow x yellow breeding indicates a misbreeding.
I have drawn upon the discussion of color genetics in Malcolm
Willis's Genetics of the
Dog (Willis, Malcolm B., Genetics of the Dog, New York: Howell
Book House, 1989), although the information is also published
elsewhere.
The inheritance effects we see are a consequence of sexual
reproduction, which
involves the "mixing and matching" of genetic material from sire and
dam to produce offspring that are genetically diverse. This genetic material
is stored and passed on in the form of DNA (deoxyribonucleic acid), which is
an enormously long molecule made up of a sequence of "bases," or
smaller molecules, linked together. DNA is actually made tip of two linked
strands wound
around each other to form a double helix, with each base on one strand linked
to a base on the other strand. These base pairs are the elements, like letters
of the alphabet, that make up the genetic code. A sequence of base pairs that
codes for a particular trait is called a gene. We think of a gene as the basic
unit of inheritance, although sometimes changes (mutations) can occur in the
sequence of base pairs that makes up a gene. Genes are strung one after another
along the DNA molecule.
The DNA of a dog exists in 78 different pieces called chromosomes (humans have
46). A close look at the chromosomes shows that they occur as pairs, one member
of each of the 39 pairs being supplied by the sire and the other coming from
the dam. While the two chromosomes in a pair are not identical, they are the
same length and contain genes for all of the same traits in the same order.
This means that each dog has two versions of every gene, one inherited from
its sire and one from its dam. They may be identical, or they may be different
alleles
of the gene. For example, a dog may have inherited the allele that codes for
black coat (B) from its sire, and the allele that codes for chocolate (b) from
its dam. It is useful to have a name for the portion of a chromosome that alternative
alleles, like
those for black and chocolate, can occupy. We call it a locus (Latin for “place”),
and so we can refer to the B locus as that part of the genetic code that determines
black vs. chocolate. (It is possible for more than two alleles to be associated
with the same locus,
but there are only two at each locus discussed here.) Yellow is determined
at
a different locus—more on that later.
The most straightforward type of gene expression is simple dominant expression,
where one allele is said to be "dominant" and the other is called “recessive.” The
dominant allele, if present, determines the trait. Since every dog has two
copies of each gene, one from the sire and one from the dam, every dog has
either the
combination, or genotype, BB, the genotype Bb, or the genotype bb.
In the case of black vs. chocolate coat color, B (black) is dominant - we use
a capital letter to indicate dominant and lower case to indicate recessive.
The B allele is needed for the Dog to be able to form black pigment. If it
is absent,
the dog will have no black on it anywhere: Its coat will be brown (unless yellow),
its eyes are apt to be yellow or gold, and its nose and the rims of its eyes,
as well as its lips, will be pigmented brown. If the dominant B allele is present,
the dog will be able to form black pigment, and its eye rims and nose will
be black, as will its coat if it doesn't happen to be yellow.
The B allele is present for both BB and Bb genotypes, so both of these will
be able to form black pigment. The b allele has no detectable effect in the
Bb dogs
This is characteristic of a recessive gene. In the bb dog, B is absent, no
black pigment will be formed, and the dog will have brown nose and eye rims
and a chocolate
coat (again, if it is not yellow). Interestingly, the breed standard for Labradors
calls for "hazel" or brown eyes in a chocolate; the chocolate Labs
brought to us for training have generally had light eyes - usually yellow or
gold.
If the genotypes of parents are known, the genotypes likely for a litter of
pups, along with the probability of each, can be predicted. Either of the sire's
genes
for a given locus can combine with either of the dam's genes for a given locus.
Constructing a Punnett Square helps keep track of the possible combinations.
A Punnett Square has a row for each allele the sire could possibly contribute,
and a column for each allele the dam Could contribute. Each entry in the square
table is the result of combining the sire's allele for that row with the dam's
allele for that column, and each possibility is equally likely. For example,
if a black stud that was known to have sired chocolate puppies (genotype Bb)
was bred to a chocolate bitch (bb), the Punnett Square would look like this:
Sire (Bb) can
contribute: |
Dam (bb) can contribute |
| |
b |
b |
| B |
Bb |
Bb |
| b |
bb |
bb |
Two of the four possibilities (50 percent) are Bb, which is black due to the
presence of one B allele. The other two are bb, chocolate, because of the absence
of the B allele. Thus we could predict that this breeding would give, for example,
five black and five chocolate pups. Keep in mind that in real life the makeup
of a litter often does not exactly match our predictions; we expect 50 percent
males and 50 percent females, but a litter might well contain three males and
eight females.
We can also reason backward from the colors in a litter to learn about the
genotypes of the parents. If the sire in the previous example was bred to a
black bitch
from black parents, and the litter included at least one chocolate puppy, we
would know the bitch was Bb. Since a chocolate puppy (bb) is chocolate only
because it received a b allele from each parent, the bitch carries the b allele,
and
since she is black, she must also carry B. The Punnett Square in this case
would be:
Sire (Bb) can
contribute: |
Dam (Bb)
can contribute |
| |
B |
b |
| B |
BB |
Bb |
| b |
Bb |
bb |
If all puppies were black, we might suspect that the bitch was BB, but we wouldn't
know for sure. Since the probable number of chocolate pups would be 25 percent
of the litter, but probabilities are often violated in a litter of pups, the
absence of chocolates would not prove that the dam was BB. If no chocolate
pups were produced in two or three breedings, we might feel pretty certain.
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Yellow is determined at a different locus, the E locus, and is completely independent
of the alleles present at the B locus. Yellow color is sometimes described
as a modification of the hair (it does not affect eye or nose pigment) and
oeeurs
only when two recessive (e) alleles are present - genotype ee. The presence
of a single dominant E (genotypes EE and Ee) will ensure a non-yellow coat,
which
may be black or chocolate depending upon the- genes present at the B locus.
As with chocolate, the recessive yellow color (ee) can only occur when an e
allele is received from each parent, so the presence of a yellow pup in a litter
is
an indication that both parents carry e. A breeding of two yellows is ee x
ee, and any way you look at it, the wily combination possible in the puppies
is ee
- also yellow. Hence the conclusion that black puppies from yellow x yellow
indicate a misbreeding.
The occurrence of black, chocolate, and yellow in Labradors is completely accounted
for by specifying the alleles present at the B and E loci, making its color
inheritance among the simplest in dogs. Other genes, which I have not seen
fully characterized, determine
how light or dark the yellow or chocolate colors may be. In a black dog, these
modifiers
are present in the genotype but invisible in the dog's color.
White markings on the chest and toes are considered to be due to additive
(polygenic) effects, called plus and minus modifiers The recessive genes
for "white
spotting" that occur in many breeds are believed to be absent in Labradors
(Willis, pp7l-73, 93-94). Dogs that inherit many minus modifiers are likely
to have white on their chests and/or feet, while dogs with many plus modifiers
will
be solid colored with no white.Equipped with an understanding of the inheritance
of B,b,E, and e alleles, we can try to determine the color genotypes of
dogs using pedigree and progeny information, and we can make predictions
about
the colors of puppies produced in certain breedings. If a dog is chocolate,
we
know it is bbE-. The dash indicates it may have either an e allele or a
second E:
If it has a yellow parent, it must have received an e from that parent
and is bbEe. If it has produced yellow pups, it must have the capability
to give
them
the e allele, and again must be bbEe. If it has been bred several times
to yellows and produced no yellow pups, it is probably bbEE. If neither
parent
is yellow,
but at least one is known to carry yellow, and the dog has never been bred
to a dog that throws yellow, it is impossible to know whether it has the
e allele
and hence carries yellow.
A yellow with a black nose and dark eyes must be B-ee. If it has a chocolate
parent or is known to have thrown chocolate pups, the "hidden" allele
must be B. Yellows with brown noses and eye rims and yellow eyes also occur,
although this color is disfavored under the breed standard. The genotype is bbee:
These dogs are both yellow and chocolate. A breeding to a black (B-E-) is expected
to produce black pups, but since the light-eyed yellow has neither the B nor
E alleles needed for a black dog, it is incorrect to say that it "carries" black.
If we know the genotypes of both sire and dam, we can construct a Punnett
Square that accounts for both B and E loci and predict the proportions
of all colors
in a litter. Consider a breeding of a sire and dam, both of which are black
but known to throw both yellow and chocolate. Such a sire was advertised
a couple
of years ago as producing an abnormally large" proportion of colored
pups when bred to bitches carrying the correct gene. Being black, sire
and dam must
both be B-E-; having produced yellow and chocolate pups, each must also
have the b and e alleles; in each case, the genotype is BbEe. A BbEe parent
can
contribute the four combinations of alleles BE, bE, Be, and be to various
pups.
Sire (BbEe) can
contribute: |
Dam (bb)
can contribute |
| |
BE |
bE |
Be |
be |
| BbEE |
BBEE |
BbEE |
BBEe |
BbEe |
| bE |
BbEE |
bbEE |
BbEe |
bbEe |
| Be |
BBEe |
BbEe |
BBee |
Bbee |
| be |
BbEe |
bbEe |
Bbee |
bbee |
All combinations are assumed to be equally likely, so if probability were followed
exactly, we would get:
| BBEE: |
1 pup in sixteen
or 6.25 percent black |
| BbEE: |
2/16
or 12.5 percent black |
| BBEe: |
2/16 or 12.5 percent
black |
| BbEe: |
4/16 or 25 percent
black |
| bbEE: |
1/16 or 6.25 percent
chocolate |
| bbEe: |
2/16 or 12.5 percent
chocolate |
| BBee: |
1/16 or 6.25 percent
yellow |
| Bbee: |
2/16 or 12.5 percent
yellow |
| bbee: |
1/16 or 6.25 percent
yellow with brown nose and light eyes |
To summarize, Out Of 16 pups, we expect nine black, three chocolate,
and four yellow, one of which has a brown nose and
light eyes. The "normal" expectation
is seven colored pups out of 16, or nearly half. We
can also predict the result of the yellow x chocolate cross mentioned
in the introduction.
Let's
arbitrarily
assume the yellow dog does not carry chocolate and
thus
has
the genotype BBee. Let's assume that the chocolate
dog does carry
one e allele
and is capable
of throwing yellow: bbEe. The Punnett Square is simplified
by the fact that the
dam can only supply one combination of alleles, Be,
and the sire can contribute two, bE and be.
Sire can
contribute (chocolate, bbEe): |
Dam (yellow,
BBee) can contribute |
| |
Be |
Be |
| bE |
BbEe |
BbEe |
| be |
Bbee |
Bbee |
Half of the puppies are BbEe (black) and half are BbEe (yellow).
With different assumptions about the "hidden" alleles,
we might have found 25 percent black with yellow,
chocolate, and lighteyed yellows
present, or
we might have
obtained an all-black litter. In any case, some
black puppies are expected, as mentioned in the
introduction.
To summarize, the black, yellow, and chocolate colors in Labs are determined
by the genes at the B and E loci. At least one copy of the B allele is needed
for dogs to form black pigment, and BB and Bb dogs will be black or yellow
with black noses. Dogs having the bb genotype are chocolate or yellow with
brown noses,
and must inherit a 1) allele from each parent. Dogs having the ee genotype
have yellow coats and must inherit an e allele from each parent. A single copy
of
the dominant E (genotypes EE and Ee) is sufficient to make the coat non-yellow
- either black or chocolate depending on what is present at the B locus I hope
this explanation of Labrador color inheritance as understood by geneticists
helps clear up the confusion involved in breeding for color and predicting
what colors will occur in a planned litter. Perhaps misbreedings. such as the
one
mentioned in the introduction, can be identified before the pups are registered.
Remember, though, that the numbers of each color in a litter, like the male-female
ratio, seldom exactly match the theoretical probabilities - so don't count
your puppies before they're whelped!
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